# Radius Measurement Using Roller Gages

Quote of the Day

There are no secrets to success. It is the result of preparation, hard work and learning from failure.

— Colin Powell, general and statesman.

## Introduction

This post will demonstrate how to measure the radius of an arc using two roller gages.  While I am a very amateur machinist, I have on occasion needed to measure the radius of an arc (i.e. partial circle) and have not been sure how to approach that measurement. It turns out to be simple given two equal diameter roller gages and a surface plate. You can determine by taking one measurement and knowing the roller gage diameter.

## Background

I have been reading this web page on metrology, and this post consists of my notes from reading this web page. The key formula for measuring the radius of curvature for an arc is given by Equation 1.

 Eq. 1 $\displaystyle R=\frac{{{{{\left( {L-d} \right)}}^{2}}}}{{8\cdot d}}$

where (referring to Figure 2).

• R is the radius of the arc we want to measure.
• d is the diameter of the two roller gages – they must be equal diameter.
• L is the distance between the two roller gages as measured from their points of maximum separation.

## Analysis

### Derivation Geometry

The geometric situation is simple and illustrated in Figure 2. The radius of the yellow circle (R) is what needs to be measured. Note that we do not need a full-circle to apply this method – we can work with an arc. The only direct measurement I need to make is of L.

### Derivation and Example

Figure 3 shows the derivation, which consists of applying the Pythagorean theorem and simplifying. I also include my calculations for the example of Figure 1. The mathematical result equaled the value on my scale drawing (Figure 1).

## Conclusion

I have struggled to measure the radii of various partially circular objects like bowls. Using a couple of roller gages gives me a simple way to measure the radius of curvature for these partial circles.

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### 3 Responses to Radius Measurement Using Roller Gages

1. Randall says:

• mathscinotes says: